Exercise 4.2 – Solution of a Quadratic Equation by Factorisation

In this post we solve Quadratic equations by Factorisation

The post cover the problems given in X grade NCERT book in Exercise 4.2.

1. Find the roots of the following quadratic equations by factorisation:

i) x2 – 3x – 10 = 0

ii) 2x2 + x – 6 = 0

iii) √2x2 + 7x + 5√2 = 0

iv) 2x2 – x + 1/8 = 0

v) 100x2 – 20x + 1 = 0

2. Solve the problems given in example 1 (given below)

i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.

(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was Rs 750. We would like to find out the number of toys produced on that day.

Let the number of toys produced per day be X

Cost of production of the toy = 55 – X

So the number of toys produced on that day is 30 or 25

3. Find two numbers whose sum is 27 and product is 182.

Hence the numbers are 13 and 14

4. Find two consecutive positive integers, sum of whose squares is 365.

Since it is given in the question that the integers are positive

Hence value of X = 13

The next consecutive number = X + 1 = 14.

5. The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

6. A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was c 90, find the number of articles produced and the cost of each article.

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